Number of primes between consecutive squares
Friend David Broadhurst corrects me as follows: Kermit suggested: > The approximate number of primes between m^2 and (m+1)^2 is > (2m+1) * product over all positive primes, p, less than or equal > to m of (p-1)/p No. That is Chebyschev's conundrum. As m tends to infinity, the left hand side is... Sign in to see full entry.