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Re: solving the two variable quadratic equation
x y + 3 x + 5 y = 62
Add 3*5 = 15 to both sides of the equation.
x y + 3 x + 5 y + 15 = 62 + 15 = 77
Factor both sides of the equation.
(x + 5) (y + 3) = 77 = 7 * 11
Then (x+5) can be 7, 11, -7, -11, 1, 77, -1, -77
and (y+3) would be 11, 7, -11, -7, 77, 1, -77, -1
giving the 8 solutions
x = 2, 6, -12, -16, -4, 72, -6, -82
y = 8, 4, -14, -10, 74, -2, -80, -4
posted by
Kermit1941
on February 24, 2015 at 11:28 AM
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I am stumped.
posted by
FormerStudentIntern
on February 23, 2015 at 11:34 AM
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posted by
Kabu
on February 23, 2015 at 11:08 AM
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