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Re: Re: Rate of winning freecell game
LOL. Leave it to me to think up a problem like that. 
posted by
TAPS.
on April 27, 2014 at 7:46 PM
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Re: Rate of winning freecell game
Ah. I posted my answer too soon. There are an infinite number of answers.
Here are the first 51 answers.
1 2221 2222
2 4442 4444
3 6663 6666
4 8884 8888
5 11105 11110
6 13326 13332
7 15547 15554
8 17768 17776
9 19989 19998
10 22210 22220
11 24431 24442
12 26652 26664
13 28873 28886
14 31094 31108
15 33315 33330
16 35536 35552
17 37757 37774
18 39978 39996
19 42199 42218
20 44420 44440
21 46641 46662
22 48862 48884
23 51083 51106
24 53304 53328
25 55525 55550
26 57746 57772
27 59967 59994
28 62188 62216
29 64409 64438
30 66630 66660
31 68851 68882
32 71072 71104
33 73293 73326
34 75514 75548
35 77735 77770
36 79956 79992
37 82177 82214
38 84398 84436
39 86619 86658
40 88840 88880
41 91061 91102
42 93282 93324
43 95503 95546
44 97724 97768
45 99945 99990
46 102166 102212
47 104387 104434
48 106608 106656
49 108829 108878
50 111050 111100
51 113271 113322
posted by
Kermit1941
on April 27, 2014 at 6:32 PM
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Re: Re: Rate of winning freecell game
That's very interesting. Apparently then there are two correct answers because at that time I had played only 2222 games and won 2221 of them. I think I've played a couple more of them since then.
posted by
TAPS.
on April 27, 2014 at 6:13 PM
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Re: Rate of winning freecell game
Thank you Taps, for this puzzle.
If you have played 111100 games, and
won 111050 of them,
then your rate of winning would be approximately 99.9549954995%
posted by
Kermit1941
on April 27, 2014 at 5:59 PM
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For years I have been playing computer Free Cell for relaxation and free thinking. At the moment my rate of winning the game is 99.9549954995%. Can you figure how many games I have played and how many I have won and lost?
posted by
TAPS.
on April 25, 2014 at 10:56 PM
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Re:
In the first of the two questions, the answer is that at 30 miles per hour, it would take one hour to go half of the sixty miles. Since the entire time as been used, it is not possible to finish the journey on time, no matter how fast he goes.
In the second of the two questions, the average velocity is
total distacnce divided by total time.
If he goes a distance d at 40 miles per hour and a distance d at 60 miles per hour,
the total distance is 2 * d,
and the total time in hours is d/40 + d/60.
The average speed will be (2 * d) / (d/40 + d/60)
The distance d will cancel in numerator and denominator.
Multiply numerator and denominator by 40 * 60.
Average speed = ( 2 * 40 * 60) / ( 40 * 60 * (1/40 + 1/60) )
= 2 * 40 * 60 / (60 + 40)
= 2 * 40 * 60 / 100
= 2 * 4 * 6
= 48
His average speed is 48 miles per hour.
posted by
Kermit1941
on April 24, 2014 at 7:06 PM
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Re:
In the first of the two questions, the answer is that at 30 miles per hour, it would take one hour to go half of the sixty miles. Since the entire time as been used, it is not possible to finish the journey on time, no matter how fast he goes.
In the second of the two questions, the average velocity is
total distacnce divided by total time.
If he goes a distance d at 40 miles per hour and a distance d at 60 miles per hour,
the total distance is 2 * d,
and the total time in hours is d/40 + d/60.
The average speed will be (2 * d) / (d/40 + d/60)
The distance d will cancel in numerator and denominator.
Multiply numerator and denominator by 40 * 60.
Average speed = ( 2 * 40 * 60) / ( 40 * 60 * (1/40 + 1/60) )
= 2 * 40 * 60 / (60 + 40)
= 2 * 40 * 60 / 100
= 2 * 4 * 6
= 48
His average speed is 48 miles per hour.
posted by
Kermit1941
on April 24, 2014 at 7:05 PM
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90 and 60?
posted by
FormerStudentIntern
on April 23, 2014 at 6:47 PM
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Just right speed to get him there on time...
posted by
Kabu
on April 23, 2014 at 5:29 PM
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