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Re: (a+b)^1 = (a+b)
We define powers of a number this way.
For a number b,
b^2 = b*b
b^3 = b * b * b
...
b^m = b * b * b .... * b ( m times)
So we extend the notation to
b^1 = 1 product of b which is just b.
b^1 = b for every number b.
Therefore (a+b)^1 = (a+b) for every number (a+b).
Also, (a+b)^0 = (a+b) multiplied by itself 0 times.
Since 1 is the identity for multiplication, 1 * e = e for every number e,
we interpret (a+b) multiplied by itself 0 times to be 1.
(a+b)^0 = 1 for all numbers (a+b).
Kermit
posted by
Kermit1941
on May 31, 2013 at 9:51 AM
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I'm afraid that I am still pondering (a + b)1 = a + b
posted by
TAPS.
on May 30, 2013 at 10:53 PM
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