Algebraic equivalent to the Pythagorean Theorem
If x = (a^2 - b^2), y = (2 a b) and z = (a^2 + b^2), then x^2 + y^2 = z^2. a = 2, b = 1, x = 2^2 - 1^2 = 4 - 1 = 3 y = 2 * 2 * 1 = 4, z = 2^2 + 1^2 = 5 3^2 + 4^2 = 5^2 9 + 16 = 25 a = 3, b = 2, x = 3^2 - 2^2 = 9 - 4 = 5 y = 2 * 3 * 2 = 12 z = 3^2 + 2^2 = 9 + 4 = 13 5^2 + 12^2 = 13^2 25 + 144 = 169 Sign in to see full entry.