Mathematics: Factoring numbers of the form (h^n + a1 h^m + a0)(h^n + b1 h^m + b0)

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Saturday, March 24, 2012

Factoring numbers of the form (h^n + a1 h^m + a0)(h^n + b1 h^m + b0)

How would you determine if a given integer were of the form (h^n + a1 h^m + a0)(h^n + b1 h^m + b0), where 2 * m > n? (h^n + a1 h^m + a0)(h^n + b1 h^m + b0) = h^(2n) + (a1+b1) h^(n+m) + a1 b1 h^(2m) + (a0+b0) h^n + (a1 b0 + b1 a0) h^m + a0 b0 = z Choose values for m and n. you can try n =... Sign in to see full entry.

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